Codeforces-Round-426#C-The Meaningless Game
The game consists of multiple rounds. Its rules are very simple: in each round, a natural number k is chosen. Then, the one who says (or barks) it faster than the other wins the round. After that, the winner’s score is multiplied by k2, and the loser’s score is multiplied by k. In the beginning of the game, both Slastyona and Pushok have scores equal to one.
Unfortunately, Slastyona had lost her notepad where the history of all n games was recorded. She managed to recall the final results for each games, though, but all of her memories of them are vague. Help Slastyona verify their correctness, or, to put it another way, for each given pair of scores determine whether it was possible for a game to finish with such result or not.
In the first string, the number of games n (1≤n≤350000) is given.
Each game is represented by a pair of scores a, b (1≤a,b≤109) – the results of Slastyona and Pushok, correspondingly.
For each pair of scores, answer "Yes" if it's possible for a game to finish with given score, and "No" otherwise.
You can output each letter in arbitrary case (upper or lower).
其实挺简单的 首先乘起来开三次方(得到加了多少次(需判断整数)) 然后判断2个条件 1：立方根是个整数 2：a和b能够整除立方根(肯定得是加的次数的倍数)## AC code:(不包含输入类)